¿Cómo listar conexiones activas / abiertas en Oracle?

Para una respuesta más completa ver: http://dbaforums.org/oracle/index.php?showtopic=16834

select
       substr(a.spid,1,9) pid,
       substr(b.sid,1,5) sid,
       substr(b.serial#,1,5) ser#,
       substr(b.machine,1,6) box,
       substr(b.username,1,10) username,
--       b.server,
       substr(b.osuser,1,8) os_user,
       substr(b.program,1,30) program
from v$session b, v$process a
where
b.paddr = a.addr
and type='USER'
order by spid; 

Cuando me gustaría ver las conexiones entrantes de nuestros servidores de aplicaciones a la base de datos, utilizo el siguiente comando:

SELECT username FROM v$session 
WHERE username IS NOT NULL 
ORDER BY username ASC;

Simple, pero eficaz.

select
  username,
  osuser,
  terminal,
  utl_inaddr.get_host_address(terminal) IP_ADDRESS
from
  v$session
where
  username is not null
order by
  username,
  osuser;

Lo siguiente le da una lista de usuarios del sistema operativo ordenados por número de conexiones, lo que es útil cuando se busca un uso excesivo de recursos.

select osuser, count(*) as active_conn_count 
from v$session 
group by osuser 
order by active_conn_count desc

Select count(1) From V$session
where status='ACTIVE'
/

select status, count(1) as connectionCount from V$SESSION group by status;

select s.sid as "Sid", s.serial# as "Serial#", nvl(s.username, ' ') as "Username", s.machine as "Machine", s.schemaname as "Schema name", s.logon_time as "Login time", s.program as "Program", s.osuser as "Os user", s.status as "Status", nvl(s.process, ' ') as "OS Process id"
from v$session s
where nvl(s.username, 'a') not like 'a' and status like 'ACTIVE'
order by 1,2

Esta consulta intenta filtrar todos los procesos en segundo plano.

select 
    count(1) "NO. Of DB Users", 
    to_char(sysdate,'DD-MON-YYYY:HH24:MI:SS') sys_time
from 
    v$session 
where 
    username is NOT  NULL;