Lista de Python ordenar en orden descendente

Question

Lista de Python ordenar en orden descendente

¿Cómo puedo ordenar esta lista en orden descendente?

timestamp = [
    "2010-04-20 10:07:30",
    "2010-04-20 10:07:38",
    "2010-04-20 10:07:52",
    "2010-04-20 10:08:22",
    "2010-04-20 10:08:22",
    "2010-04-20 10:09:46",
    "2010-04-20 10:10:37",
    "2010-04-20 10:10:58",
    "2010-04-20 10:11:50",
    "2010-04-20 10:12:13",
    "2010-04-20 10:12:13",
    "2010-04-20 10:25:38"
]

267

python sorting reverse

Author: Mark Amery, 2010-11-15

Source

5 answers

Esto le dará una versión ordenada de la matriz.

sorted(timestamp, reverse=True)

Si desea ordenar en su lugar:

timestamp.sort(reverse=True)

314

Author: Marcelo Cantos,
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2010-11-15 10:47:15

Simplemente puedes hacer esto:

timestamp.sort(reverse=True)

41

Author: Wolph,
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2016-11-13 14:59:21

Dado que su lista ya está en orden ascendente, podemos simplemente invertir la lista.

>>> timestamp.reverse()
>>> timestamp
['2010-04-20 10:25:38', 
'2010-04-20 10:12:13', 
'2010-04-20 10:12:13', 
'2010-04-20 10:11:50', 
'2010-04-20 10:10:58', 
'2010-04-20 10:10:37', 
'2010-04-20 10:09:46', 
'2010-04-20 10:08:22',
'2010-04-20 10:08:22', 
'2010-04-20 10:07:52', 
'2010-04-20 10:07:38', 
'2010-04-20 10:07:30']

7

Author: Russell Dias,
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2010-11-15 10:42:18

Simplemente escribe:

timestamp.sort()
timestamp=timestamp[::-1]

3

Author: mostafa elmadany,
Warning: date(): Invalid date.timezone value 'Europe/Kyiv', we selected the timezone 'UTC' for now. in /var/www/agent_stack/data/www/ajaxhispano.com/template/agent.layouts/content.php on line 61
2017-10-06 17:13:58

score 307 · Accepted Answer

En una línea, usando un lambda:

timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True)

Pasando una función a list.sort:

def foo(x):
    return time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6]

timestamp.sort(key=foo, reverse=True)

307

Author: Ignacio Vazquez-Abrams,
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2018-01-11 06:16:12